SAFeTRADE
656 posts
msg #161988
- Ignore SAFeTRADE |
10/8/2025 10:49:21 AM
buy when high reaches a new 13 day high and
has an increasing ma(45) and
8 day low at least 1 step higher preferably 2
coding looks like :
set{13hi,count(high reached a new 13 day high,1)}
set{incm45,count(ma(45) > ma(45) 4 days ago,1)}
how to code 8 day low 1 or 2 steps higher?
Look at NVDA below to see stair step of 8 day low
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SAFeTRADE
656 posts
msg #161989
- Ignore SAFeTRADE |
10/8/2025 11:07:20 AM
This my first attempt :
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SAFeTRADE
656 posts
msg #161990
- Ignore SAFeTRADE |
10/8/2025 11:55:04 AM
Attempt 2:
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SAFeTRADE
656 posts
msg #161991
- Ignore SAFeTRADE |
10/8/2025 2:51:51 PM
While I have you attentiin, have any of you used AI to build a python filter as an example a Weinstein
filter?
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xarlor
619 posts
msg #161992
- Ignore xarlor |
10/8/2025 3:40:35 PM
Try this. Increase the days to count to fit your preference and make the last line your preference - 1.
set{lowstepper1,low 8-day low}
set{lowstepper2,low 8-day low 1 day ago}
set{lowstepper,count(lowstepper1 >= lowstepper2,8)}
lowstepper > 7
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SAFeTRADE
656 posts
msg #161993
- Ignore SAFeTRADE |
10/8/2025 5:20:52 PM
Thanks xarlor your code gave me an idea. This is a much cleaner chart with the signals clearly visible.
This stepper idea comes from Mark Minervini, he also uses VCP which I am attempting to code in
stockfetcher.. Stepper signaling 1 means itis a stepper from on e to infinity (well not infinity only until
it is not a stepper). I also added dn_step to show when the run potentially ends.
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